Optimal. Leaf size=83 \[ \frac{b e \text{PolyLog}\left (2,-\frac{c+d x+1}{-c-d x+1}\right )}{2 d}-\frac{e \left (a+b \tanh ^{-1}(c+d x)\right )^2}{2 b d}+\frac{e \log \left (\frac{2}{-c-d x+1}\right ) \left (a+b \tanh ^{-1}(c+d x)\right )}{d} \]
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Rubi [A] time = 0.262931, antiderivative size = 83, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 5, integrand size = 32, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.156, Rules used = {12, 5984, 5918, 2402, 2315} \[ \frac{b e \text{PolyLog}\left (2,-\frac{c+d x+1}{-c-d x+1}\right )}{2 d}-\frac{e \left (a+b \tanh ^{-1}(c+d x)\right )^2}{2 b d}+\frac{e \log \left (\frac{2}{-c-d x+1}\right ) \left (a+b \tanh ^{-1}(c+d x)\right )}{d} \]
Antiderivative was successfully verified.
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Rule 12
Rule 5984
Rule 5918
Rule 2402
Rule 2315
Rubi steps
\begin{align*} \int \frac{(c e+d e x) \left (a+b \tanh ^{-1}(c+d x)\right )}{1-(c+d x)^2} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{e x \left (a+b \tanh ^{-1}(x)\right )}{1-x^2} \, dx,x,c+d x\right )}{d}\\ &=\frac{e \operatorname{Subst}\left (\int \frac{x \left (a+b \tanh ^{-1}(x)\right )}{1-x^2} \, dx,x,c+d x\right )}{d}\\ &=-\frac{e \left (a+b \tanh ^{-1}(c+d x)\right )^2}{2 b d}+\frac{e \operatorname{Subst}\left (\int \frac{a+b \tanh ^{-1}(x)}{1-x} \, dx,x,c+d x\right )}{d}\\ &=-\frac{e \left (a+b \tanh ^{-1}(c+d x)\right )^2}{2 b d}+\frac{e \left (a+b \tanh ^{-1}(c+d x)\right ) \log \left (\frac{2}{1-c-d x}\right )}{d}-\frac{(b e) \operatorname{Subst}\left (\int \frac{\log \left (\frac{2}{1-x}\right )}{1-x^2} \, dx,x,c+d x\right )}{d}\\ &=-\frac{e \left (a+b \tanh ^{-1}(c+d x)\right )^2}{2 b d}+\frac{e \left (a+b \tanh ^{-1}(c+d x)\right ) \log \left (\frac{2}{1-c-d x}\right )}{d}+\frac{(b e) \operatorname{Subst}\left (\int \frac{\log (2 x)}{1-2 x} \, dx,x,\frac{1}{1-c-d x}\right )}{d}\\ &=-\frac{e \left (a+b \tanh ^{-1}(c+d x)\right )^2}{2 b d}+\frac{e \left (a+b \tanh ^{-1}(c+d x)\right ) \log \left (\frac{2}{1-c-d x}\right )}{d}+\frac{b e \text{Li}_2\left (1-\frac{2}{1-c-d x}\right )}{2 d}\\ \end{align*}
Mathematica [A] time = 0.116181, size = 114, normalized size = 1.37 \[ -\frac{e \left (-2 b \text{PolyLog}\left (2,\frac{1}{2} (-c-d x+1)\right )+2 b \text{PolyLog}\left (2,\frac{1}{2} (c+d x+1)\right )+4 a \log (-c-d x+1)+4 a \log (c+d x+1)-b \log ^2(-c-d x+1)+b \log ^2(c+d x+1)+b \log (4) \log (c+d x-1)-b \log (4) \log (c+d x+1)\right )}{8 d} \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.058, size = 194, normalized size = 2.3 \begin{align*} -{\frac{ae\ln \left ( dx+c-1 \right ) }{2\,d}}-{\frac{ae\ln \left ( dx+c+1 \right ) }{2\,d}}-{\frac{be{\it Artanh} \left ( dx+c \right ) \ln \left ( dx+c-1 \right ) }{2\,d}}-{\frac{be{\it Artanh} \left ( dx+c \right ) \ln \left ( dx+c+1 \right ) }{2\,d}}-{\frac{be \left ( \ln \left ( dx+c-1 \right ) \right ) ^{2}}{8\,d}}+{\frac{be}{2\,d}{\it dilog} \left ({\frac{1}{2}}+{\frac{dx}{2}}+{\frac{c}{2}} \right ) }+{\frac{be\ln \left ( dx+c-1 \right ) }{4\,d}\ln \left ({\frac{1}{2}}+{\frac{dx}{2}}+{\frac{c}{2}} \right ) }+{\frac{be}{4\,d}\ln \left ( -{\frac{dx}{2}}-{\frac{c}{2}}+{\frac{1}{2}} \right ) \ln \left ({\frac{1}{2}}+{\frac{dx}{2}}+{\frac{c}{2}} \right ) }-{\frac{be\ln \left ( dx+c+1 \right ) }{4\,d}\ln \left ( -{\frac{dx}{2}}-{\frac{c}{2}}+{\frac{1}{2}} \right ) }+{\frac{be \left ( \ln \left ( dx+c+1 \right ) \right ) ^{2}}{8\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{2} \, b c e{\left (\frac{\log \left (d x + c + 1\right )}{d} - \frac{\log \left (d x + c - 1\right )}{d}\right )} \operatorname{artanh}\left (d x + c\right ) - \frac{1}{2} \, a d e{\left (\frac{{\left (c + 1\right )} \log \left (d x + c + 1\right )}{d^{2}} - \frac{{\left (c - 1\right )} \log \left (d x + c - 1\right )}{d^{2}}\right )} + \frac{1}{2} \, a c e{\left (\frac{\log \left (d x + c + 1\right )}{d} - \frac{\log \left (d x + c - 1\right )}{d}\right )} + \frac{1}{8} \, b d e{\left (\frac{2 \,{\left (c + 1\right )} \log \left (d x + c + 1\right ) \log \left (-d x - c + 1\right ) -{\left (c - 1\right )} \log \left (-d x - c + 1\right )^{2}}{d^{2}} - 4 \, \int \frac{{\left (c^{2} +{\left (c d + 3 \, d\right )} x + 2 \, c + 1\right )} \log \left (d x + c + 1\right )}{2 \,{\left (d^{3} x^{2} + 2 \, c d^{2} x + c^{2} d - d\right )}}\,{d x}\right )} - \frac{{\left (\log \left (d x + c + 1\right )^{2} - 2 \, \log \left (d x + c + 1\right ) \log \left (d x + c - 1\right ) + \log \left (d x + c - 1\right )^{2}\right )} b c e}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{a d e x + a c e +{\left (b d e x + b c e\right )} \operatorname{artanh}\left (d x + c\right )}{d^{2} x^{2} + 2 \, c d x + c^{2} - 1}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} - e \left (\int \frac{a c}{c^{2} + 2 c d x + d^{2} x^{2} - 1}\, dx + \int \frac{a d x}{c^{2} + 2 c d x + d^{2} x^{2} - 1}\, dx + \int \frac{b c \operatorname{atanh}{\left (c + d x \right )}}{c^{2} + 2 c d x + d^{2} x^{2} - 1}\, dx + \int \frac{b d x \operatorname{atanh}{\left (c + d x \right )}}{c^{2} + 2 c d x + d^{2} x^{2} - 1}\, dx\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int -\frac{{\left (d e x + c e\right )}{\left (b \operatorname{artanh}\left (d x + c\right ) + a\right )}}{{\left (d x + c\right )}^{2} - 1}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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